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/** | ||
* Definition for a binary tree node. | ||
* struct TreeNode { | ||
* int val; | ||
* TreeNode *left; | ||
* TreeNode *right; | ||
* TreeNode() : val(0), left(nullptr), right(nullptr) {} | ||
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} | ||
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} | ||
* }; | ||
*/ | ||
class BSTIterator { | ||
vector<int> q; | ||
int it{0}; | ||
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void helper(TreeNode* cur) { | ||
if(!cur) return; | ||
helper(cur->left); | ||
q.emplace_back(cur->val); | ||
helper(cur->right); | ||
} | ||
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public: | ||
BSTIterator(TreeNode* root) { | ||
helper(root); | ||
} | ||
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int next() { | ||
return q[it++]; | ||
} | ||
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bool hasNext() { | ||
return it < q.size(); | ||
} | ||
}; | ||
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/** | ||
* Your BSTIterator object will be instantiated and called as such: | ||
* BSTIterator* obj = new BSTIterator(root); | ||
* int param_1 = obj->next(); | ||
* bool param_2 = obj->hasNext(); | ||
*/ |