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Faster Call for
CompiledSDFG
#1467Faster Call for
CompiledSDFG
#1467Changes from 11 commits
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This section may also not belong in a fast call
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I do not understand this. According to my understand this calls the actual compiled function. Thus without it nothing would be done, or do I miss something here?
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Look at the line the comment points to: the GPU runtime check belongs in the normal call, not fast call. If you want to ensure execution is fast you can skip this check, which might be expensive.
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I decided to give
fast_call()
the possibility of performing the check, however it is disabled by default. The main reason for that was removing of code duplication.Thanks for the explanation, so the comment always points to the "last line that is shown"?