add task solution #2172
add task solution #2172
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Thank you for your hard work on this pull request! 😊 While your solution meets many of the task requirements, there are a few critical issues that need to be addressed to ensure the formatDate function works correctly:
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Delimiter Handling: The use of
newDeleteLastElementas a delimiter for joining date parts may not align with the expected format intoFormat. Ensure that the delimiter matches the intended output format. -
Year Conversion Logic: The conversion from 'YY' to 'YYYY' relies on a hardcoded threshold ('30'), which might not be suitable for all scenarios. Consider making this logic more flexible or configurable to accommodate different use cases.
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Handling 'YYYY' in
fromFormat: The current logic assumes 'YYYY' is always present infromFormat, which might not be true. Ensure your code can handle cases where 'YYYY' is absent. -
Correct Population of
partOfDate: ThepartOfDatearray is not correctly populated. Make sure it accurately reflects the segments of the date string based onfromFormatCopy. -
Date String Splitting: The method for splitting the date string using
deleteLastElementis flawed. This approach assumes the last element offromFormatis a delimiter, which may not always be the case. Consider a more robust parsing method.
Please address these issues to ensure the function performs as expected. Keep up the great work, and don't hesitate to reach out if you need further clarification or assistance! 🚀
✨ Please rate this review in the Platform's notification center. I will be grateful for your feedback! ✨
🔄 Fix the issues, commit the changes, and then re-request my review using the Re-request review button in the Reviewers tab.
src/formatDate.js
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| const deleteLastElement = fromFormatCopy.pop(); | ||
| const partOfDate = date.split(deleteLastElement); |
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The logic for splitting the date string using deleteLastElement is incorrect. This assumes that the last element of fromFormat is a delimiter, which may not always be the case. Consider using a more robust method to parse the date string based on the format provided.
src/formatDate.js
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| const partsOfDate = {}; | ||
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| fromFormatCopy.forEach((part, index) => { | ||
| partsOfDate[part] = partOfDate[index]; |
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The partOfDate array is not correctly populated. Since partOfDate is derived from splitting the date string, ensure that it contains the correct segments corresponding to fromFormatCopy. Otherwise, partsOfDate will not be populated correctly.
src/formatDate.js
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| if (toFormatCopy.includes('YY') && partsOfDate['YYYY']) { | ||
| partsOfDate['YY'] = partsOfDate['YYYY'].slice(-2); | ||
| } |
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The conversion from 'YYYY' to 'YY' assumes that 'YYYY' is always present, which might not be the case. Ensure that the logic handles cases where 'YYYY' is not provided in fromFormat.
src/formatDate.js
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| if (toFormatCopy.includes('YYYY') && partsOfDate['YY']) { | ||
| partsOfDate['YYYY'] = | ||
| partsOfDate['YY'] < '30' | ||
| ? '20' + partsOfDate['YY'] | ||
| : '19' + partsOfDate['YY']; | ||
| } |
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The conversion from 'YY' to 'YYYY' is based on a hardcoded threshold ('30'), which might not be suitable for all use cases. Consider making this logic more flexible or configurable.
src/formatDate.js
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| const newDeleteLastElement = toFormatCopy.pop(); | ||
| const newDate = toFormatCopy | ||
| .map((part) => partsOfDate[part]) | ||
| .join(newDeleteLastElement); |
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Similar to the issue with fromFormat, using newDeleteLastElement as a delimiter for joining the date parts may not be correct. Ensure that the delimiter used matches the expected format in toFormat.
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Review Summary
Great job on implementing the formatDate function! 🎉 Your code meets the task requirements, and it's clear you've put in a lot of effort. However, there are a few critical issues that need attention to ensure the function works flawlessly:
-
Delimiter Handling: The use of
newSeparatorfor joining date parts may not align with the expected format intoFormat. Ensure that the delimiter matches the intended output format. -
Year Conversion Logic: The conversion logic from 'YY' to 'YYYY' uses a hardcoded threshold ('30'), which might not be suitable for all scenarios. Consider making this logic more flexible or configurable.
-
Handling 'YYYY' in
fromFormat: The logic assumes that 'YYYY' is always present infromFormat, which might not be true. Ensure that the code can handle cases where 'YYYY' is absent. -
Date String Splitting: The logic assumes that the last element of
fromFormatis a separator, which may not always be the case. Consider using a more robust method to determine the separator.
These issues should be addressed in future iterations to avoid similar problems. Keep up the great work, and use this feedback to refine your skills further. Remember, learning from mistakes is a crucial part of the development process. 😊
✨ Please rate this review in the Platform's notification center. I will be grateful for your feedback! ✨
| const separator = fromFormatCopy.pop(); | ||
| const parts = date.split(separator); |
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The logic assumes that the last element of fromFormat is a separator, which may not always be the case. This could lead to incorrect splitting of the date string. Consider using a more robust method to determine the separator.
| if (toFormatCopy.includes('YY') && dateParts['YYYY']) { | ||
| dateParts['YY'] = dateParts['YYYY'].slice(-2); | ||
| } |
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The logic here assumes that 'YYYY' is always present in fromFormat, which might not be true. Ensure that the code can handle cases where 'YYYY' is absent.
| if (toFormatCopy.includes('YYYY') && dateParts['YY']) { | ||
| dateParts['YYYY'] = | ||
| dateParts['YY'] < '30' ? '20' + dateParts['YY'] : '19' + dateParts['YY']; | ||
| } |
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The conversion logic from 'YY' to 'YYYY' uses a hardcoded threshold ('30'), which might not be suitable for all scenarios. Consider making this logic more flexible or configurable.
| const newSeparator = toFormatCopy.pop(); | ||
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| const newDate = toFormatCopy | ||
| .map((part) => dateParts[part]) | ||
| .join(newSeparator); |
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The use of newSeparator as a delimiter for joining date parts may not align with the expected format in toFormat. Ensure that the delimiter matches the intended output format.
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