Solution #2163
Solution #2163
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Great job on implementing the formatDate function! 🎉 Your solution meets the task requirements and constraints effectively. While there are a few areas for improvement, such as handling unexpected year values and making the separator identification more robust, these do not critically impact the functionality of your code. Keep up the good work, and consider these suggestions for future enhancements! 😊
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| @@ -8,7 +8,30 @@ | |||
| * @returns {string} | |||
| */ | |||
| function formatDate(date, fromFormat, toFormat) { | |||
| // write code here | |||
| const separator = fromFormat[3]; | |||
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The code assumes that the separator is always at the fourth position in the fromFormat array. This assumption might not hold true for all date formats. Consider a more flexible approach to determine the separator.
| dateObj['YYYY'] = year < 30 ? `20${dateObj['YY']}` : `19${dateObj['YY']}`; | ||
| } | ||
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| const newSeparator = toFormat[3]; |
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Similar to the issue with fromFormat, the code assumes the separator is at the fourth position in the toFormat array. This might not be accurate for all formats. Consider a more robust method to identify the separator.
| if (fromFormat.includes('YYYY') && toFormat.includes('YY')) { | ||
| dateObj['YY'] = dateObj['YYYY'].slice(-2); | ||
| } else if (fromFormat.includes('YY') && toFormat.includes('YYYY')) { | ||
| const year = parseInt(dateObj['YY'], 10); | ||
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| dateObj['YYYY'] = year < 30 ? `20${dateObj['YY']}` : `19${dateObj['YY']}`; | ||
| } |
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The logic for converting between 'YYYY' and 'YY' formats is correct, but it doesn't account for invalid or unexpected year values. Consider adding validation to ensure the year values are within a reasonable range.
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