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all: | ||
gcc -O2 -o test combination_sum.c |
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#include <stdio.h> | ||
#include <stdlib.h> | ||
#include <string.h> | ||
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static void insert_sort(int *a, int size) | ||
{ | ||
int i, j; | ||
for (i = 1; i < size; i++) { | ||
int tmp = a[i]; | ||
for (j = i - 1; j >= 0 && tmp < a[j]; j--) { | ||
a[j + 1] = a[j]; | ||
} | ||
a[j + 1] = tmp; | ||
} | ||
} | ||
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static void combination_recursive(int *nums, int size, int start, int target, | ||
int *solution, int len, | ||
int **results, int *column_sizes, int *count) | ||
{ | ||
int i; | ||
if (target > 0) { | ||
for (i = start; i < size; i++) { | ||
if (i > 0 && nums[i] == nums[i - 1]) { | ||
continue; | ||
} | ||
/* You may dump the content of the solution here, and you would find | ||
* the order of element represents the number of nested layers, and | ||
* the element at the specific order represents the iteration from | ||
* the start in the current recursive layer. | ||
*/ | ||
solution[len++] = nums[i]; | ||
combination_recursive(nums, size, i, target - nums[i], solution, len, results, column_sizes, count); | ||
len--; | ||
} | ||
} else if (target == 0) { | ||
results[*count] = malloc(len * sizeof(int)); | ||
memcpy(results[*count], solution, len * sizeof(int)); | ||
column_sizes[*count] = len; | ||
(*count)++; | ||
} | ||
} | ||
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/** | ||
** Return an array of arrays of size *returnSize. | ||
** The sizes of the arrays are returned as *columnSizes array. | ||
** Note: Both returned array and *columnSizes array must be malloced, assume caller calls free(). | ||
**/ | ||
int** combinationSum(int* candidates, int candidatesSize, int target, int** columnSizes, int* returnSize) { | ||
insert_sort(candidates, candidatesSize); | ||
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int *solution = malloc(target * sizeof(int)); | ||
int **results = malloc(100 * sizeof(int *)); | ||
*columnSizes = malloc(100 * sizeof(int)); | ||
*returnSize = 0; | ||
combination_recursive(candidates, candidatesSize, 0, target, solution, 0, results, *columnSizes, returnSize); | ||
return results; | ||
//for (i = 0; i < candidatesSize; i++) { | ||
// //int *columns = malloc(); | ||
// for (j = 1; candidates[i] * j < target, j++) { | ||
// for (k = i + 1; k < candidatesSize; k++) { | ||
// | ||
// } | ||
// int remain = target - candidates[i] * j; | ||
// if (remain == 0) { | ||
// int *column = malloc(sizeof(int)); | ||
// if (count + 1 >= cap) { | ||
// cap *= 2; | ||
// columnSizes = realloc(columnSizes, cap * sizeof(int *)); | ||
// } | ||
// columnSizes[count++] = column; | ||
// } else { | ||
// k = i + 1; | ||
// } | ||
// } | ||
//} | ||
} | ||
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int main(int argc, char **argv) | ||
{ | ||
if (argc <= 2) { | ||
fprintf(stderr, "Usage: ./test target array...\n"); | ||
exit(-1); | ||
} | ||
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int i, j, count = 0; | ||
int target = atoi(argv[1]); | ||
int *nums = malloc((argc - 2) * sizeof(int)); | ||
for (i = 0; i < argc - 2; i++) { | ||
nums[i] = atoi(argv[i + 2]); | ||
} | ||
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int *sizes; | ||
int **lists = combinationSum(nums, argc - 2, target, &sizes, &count); | ||
for (i = 0; i < count; i++) { | ||
for (j = 0; j < sizes[i]; j++) { | ||
printf("%d ", lists[i][j]); | ||
} | ||
printf("\n"); | ||
} | ||
return 0; | ||
} |
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all: | ||
gcc -O2 -o test combination_sum.c |
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#include <stdio.h> | ||
#include <stdlib.h> | ||
#include <stdbool.h> | ||
#include <string.h> | ||
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static bool exist(int **results, int count, int *solution, int len) | ||
{ | ||
int i; | ||
for (i = 0; i < count; i++) { | ||
if (!memcmp(results[i], solution, len * sizeof(int))) { | ||
return true; | ||
} | ||
} | ||
return false; | ||
} | ||
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static void insert_sort(int *a, int size) | ||
{ | ||
int i, j; | ||
for (i = 1; i < size; i++) { | ||
int tmp = a[i]; | ||
for (j = i - 1; j >= 0 && tmp < a[j]; j--) { | ||
a[j + 1] = a[j]; | ||
} | ||
a[j + 1] = tmp; | ||
} | ||
} | ||
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static void combination_recursive(int *nums, int size, int start, int target, | ||
int *solution, int len, | ||
int **results, int *column_sizes, int *count) | ||
{ | ||
int i; | ||
if (target > 0) { | ||
for (i = start; i < size; i++) { | ||
/* You may dump the content of the solution here, and you would find | ||
* the order of element represents the number of nested layers, and | ||
* the element at the specific order represents the iteration from | ||
* the start in the current recursive layer. | ||
*/ | ||
solution[len++] = nums[i]; | ||
combination_recursive(nums, size, i + 1, target - nums[i], solution, | ||
len, results, column_sizes, count); | ||
len--; | ||
} | ||
} else if (target == 0) { | ||
if (!exist(results, *count, solution, len)) { | ||
results[*count] = malloc(len * sizeof(int)); | ||
memcpy(results[*count], solution, len * sizeof(int)); | ||
column_sizes[*count] = len; | ||
(*count)++; | ||
} | ||
} | ||
} | ||
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/** | ||
** Return an array of arrays of size *returnSize. | ||
** The sizes of the arrays are returned as *columnSizes array. | ||
** Note: Both returned array and *columnSizes array must be malloced, assume caller calls free(). | ||
**/ | ||
static int** combinationSum(int* candidates, int candidatesSize, int target, int** columnSizes, int* returnSize) | ||
{ | ||
insert_sort(candidates, candidatesSize); | ||
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int *solution = malloc(target * sizeof(int)); | ||
int **results = malloc(100 * sizeof(int *)); | ||
*columnSizes = malloc(100 * sizeof(int)); | ||
*returnSize = 0; | ||
combination_recursive(candidates, candidatesSize, 0, target, solution, 0, results, *columnSizes, returnSize); | ||
return results; | ||
} | ||
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int main(int argc, char **argv) | ||
{ | ||
int i, j, count = 0; | ||
int target = atoi(argv[1]); | ||
int *nums = malloc((argc - 2) * sizeof(int)); | ||
for (i = 0; i < argc - 2; i++) { | ||
nums[i] = atoi(argv[i + 2]); | ||
} | ||
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int *sizes; | ||
int **lists = combinationSum(nums, argc - 2, target, &sizes, &count); | ||
for (i = 0; i < count; i++) { | ||
for (j = 0; j < sizes[i]; j++) { | ||
printf("%d ", lists[i][j]); | ||
} | ||
printf("\n"); | ||
} | ||
return 0; | ||
} |