Merge pull request #129 from jverzani/v0.19a

updates after up

quarto/alternatives/symbolics.qmd

@@ -838,10 +838,18 @@ substitute(ΣqᵢΘᵢ, d)
 The package provides an algorithm for the creation of candidates and the means to solve when possible. The `integrate` function is the main entry point. It returns three values: `solved`, `unsolved`, and `err`. The `unsolved` is the part of the integrand which can not be solved through this package. It is  `0` for a given problem when `integrate` is successful in identifying an antiderivative, in which case `solved` is the answer. The value of `err` is a bound on the numerical error introduced by the algorithm.
 
 
+::: {.callout-note}
+### This is currently broken
+
+The following isn't working with `SymbolicNumericIntegration` version `v"1.4.0"`. For now, the cells are not evaluated.
+
+:::
+
 To see, we have:
 
 
 ```{julia}
+#| eval: false
 using SymbolicNumericIntegration
 @variables x
 
@@ -852,6 +860,7 @@ The second term is `0`, as this integrand has an identified antiderivative.
 
 
 ```{julia}
+#| eval: false
 integrate(exp(x^2) + sin(x))
 ```
 
@@ -862,13 +871,15 @@ Powers of trig functions have antiderivatives, as can be deduced using integrati
 
 
 ```{julia}
+#| eval: false
 u,v,w = integrate(sin(x)^5)
 ```
 
 The derivative of `u` matches up to some numeric tolerance:
 
 
 ```{julia}
+#| eval: false
 Symbolics.derivative(u, x) - sin(x)^5
 ```
 
@@ -879,6 +890,7 @@ The integration of rational functions (ratios of polynomials) can be done algori
 
 
 ```{julia}
+#| eval: false
 import SymbolicNumericIntegration: factor_rational
 @variables x
 u = (1 + x + x^2)/ (x^2 -2x + 1)
@@ -889,13 +901,15 @@ The summands in `v` are each integrable. We can see that `v` is a reexpression t
 
 
 ```{julia}
+#| eval: false
 simplify(u - v)
 ```
 
 The algorithm is numeric, not symbolic. This can be seen in these two factorizations:
 
 
 ```{julia}
+#| eval: false
 u = 1 / expand((x^2-1)*(x-2)^2)
 v = factor_rational(u)
 ```
@@ -904,6 +918,7 @@ or
 
 
 ```{julia}
+#| eval: false
 u = 1 / expand((x^2+1)*(x-2)^2)
 v = factor_rational(u)
 ```

quarto/derivatives/newtons_method.qmd

@@ -368,6 +368,7 @@ For the function $f(x) = \cos(x) - x$, we see that SymPy can not solve symbolica
 
 
 ```{julia}
+#| error: true
 @syms x::real
 solve(cos(x) - x, x)
 ```

quarto/differentiable_vector_calculus/plots_plotting.qmd

@@ -359,7 +359,7 @@ We can parameterize the sphere by plotting values for $x$, $y$, and $z$ produced
 
 
 ```{julia}
-#| hold: true
+#| eval: false
 thetas = range(0, stop=pi,   length=50)
 phis   = range(0, stop=pi/2, length=50)
 
@@ -379,6 +379,7 @@ For convenience, the `plot_parametric` function from `CalculusWithJulia` can pro
 
 
 ```{julia}
+#| eval: false
 #| hold: true
 F(theta, phi) = [X(1, theta, phi), Y(1, theta, phi), Z(1, theta, phi)]
 plot_parametric(0..pi, 0..pi/2, F)
@@ -401,6 +402,7 @@ $$
 To illustrate, we have:
 
 ```{julia}
+#| eval: false
 # cf. https://discourse.julialang.org/t/general-plotting-code-for-cone-in-3d-with-glmakie-or-plots/92104/3
 
 basecurve(u) = [cos(u), sin(u) + sin(u/2), 0]
@@ -419,6 +421,7 @@ To use it, we see what happens when a sphere if rendered:
 
 
 ```{julia}
+#| eval: false
 #| hold: true
 f(x,y,z) = x^2 + y^2 + z^2 - 25
 CalculusWithJulia.plot_implicit_surface(f)
@@ -428,6 +431,7 @@ This figure comes from a February 14, 2019 article in the [New York Times](https
 
 
 ```{julia}
+#| eval: false
 #| hold: true
 a,b = 1,3
 f(x,y,z) = (x^2+((1+b)*y)^2+z^2-1)^3-x^2*z^3-a*y^2*z^3