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jirilebl committed Dec 7, 2023
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Expand Up @@ -15579,7 +15579,7 @@ \section{Varieties} \label{sec:varieties}
After a small linear change of coordinates, the
Weierstrass preparation theorem applies and we can assume that $f$ is a
Weierstrass polynomial. Write the variables as
$(z_1,\ldots,z_{n-1},z_n) = (z',z_n)$ as before.
$(z_1,\ldots,z_{n-1},z_n) = (z',z_n)$.
In some neighborhood $V$ of the origin (where $V \subset U$),
\thmref{thm:discrthm} applies to $f$, so
let $\Delta(z')$ denote the discriminant function.
Expand All @@ -15597,12 +15597,14 @@ \section{Varieties} \label{sec:varieties}
After a linear change of variables in $z'$,
we apply the preparation theorem in $z'$ with respect to $z_{n-1}$
and get $\Delta = u P$ in some neighborhood of $0$,
where $u$ is a unit $P$ is a Weierstrass polynomial
in $z_{n-1}$ with coefficients that only depend on $z_1,\ldots,z_{n-2}$.
where $u$ is a unit and $P$ is a Weierstrass polynomial
in $z_{n-1}$ with coefficients that only depend on
$z_1,\ldots,z_{n-2}$.
Let $\Delta'$ be the discriminant for $P$ and repeat the procedure
above. Either $\Delta'$ does not vanish some point of $X$, in which case
we apply the induction hypothesis as above, or near the
origin $X$ is contained in the zero set of $\Delta'$. If $X$ is contained
above. Either $\Delta'$ is nonzero at some point of $X$,
in which case we apply the induction hypothesis as above,
or near the
origin, $X$ is contained in the zero set of $\Delta'$. If $X$ is contained
in the zero set of $\Delta'$, we again apply the preparation theorem
and get a polynomial in $z_{n-2}$ with coefficients depending only on
$z_1,\ldots,z_{n-3}$. Rinse and repeat. Either at some point we could
Expand All @@ -15620,7 +15622,7 @@ \section{Varieties} \label{sec:varieties}
\begin{thm} \label{thm:varietysingularity}
Let $U \subset \C^n$ be open and let $X \subset U$
be a subvariety, then
$X_{\mathit{sing}} \subset X$ is a subvariety
$X_{\mathit{sing}} \subset X$ is a subvariety,
which is nowhere dense in $X$
and $\dim X_{\mathit{sing}} < \dim X$.
\end{thm}
Expand Down Expand Up @@ -15652,29 +15654,33 @@ \section{Hypervarieties} \label{section:hypervarieties}
\end{thm}

\begin{proof}
We need to find a function that vanishes on $(X,p)$ and divides every other
function that vanishes there.
There has to exist at least one germ of a function that vanishes on $(X,p)$
We need to find a function that vanishes on $(X,p)$
and divides every other function that vanishes there.
There must exist at least one germ of a function that vanishes
on $X$ near $p$
(although it could vanish on a larger set).
Assume $p=0$, and after a linear change
of coordinates assume we can apply the Weierstrass preparation theorem
to the function. Taking representatives of the germs, we assume
$X$ is a pure codimension-$1$ subvariety of a small enough
Without loss of generality, assume $p=0$
and after a linear change
of coordinates the Weierstrass preparation theorem applies.
More precisely,
suppose $X$ is a pure codimension-$1$ subvariety
of a small enough
neighborhood
$U' \times D \subset \C^{n-1} \times \C$ of the origin, where $D$ is a disc,
and the function that vanishes on $X$ is a
Weierstrass polynomial $P(z',z_n)$ defined for $z' \in U'$, and
all zeros of $z_n \mapsto P(z',z_n)$ are in $D$ for $z' \in U$.

\thmref{thm:discrthm} applies. Let
$E \subset U'$ be the discriminant set, a zero set of a
holomorphic function.
On $U' \setminus E$, there are a certain number of geometrically
distinct zeros of $z_n \mapsto P(z',z_n)$.

Let $X'$ be a topological component of $X \setminus ( E \times D )$.
Above each point $z' \in U' \setminus E$, let
$\alpha_1(z'),\ldots,\alpha_k(z')$ denote the distinct zeros that are in $X'$,
Let $X'$ be a topological component of
$X \setminus ( E \times D )$.
Above each $z' \in U' \setminus E$,
let $\alpha_1(z'),\ldots,\alpha_k(z')$
denote the distinct zeros that are in $X'$,
that is, $\bigl(z',\alpha_\ell(z')\bigr) \in X'$.
If $\alpha_\ell$ is a holomorphic function in some small neighborhood and
$\bigl(z',\alpha_\ell(z')\bigr) \in X'$ at one point, then
Expand All @@ -15687,7 +15693,7 @@ \section{Hypervarieties} \label{section:hypervarieties}
such geometrically distinct zeros in $X'$ above each point in
$U' \setminus E$ is locally constant.
As $U' \setminus E$ is connected
(\exerciseref{exercise:connectedcomplement})
(\exerciseref{exercise:connectedcomplement}),
there exists a unique $k$. Take
\begin{equation*}
F(z',z_n) = \prod_{\ell=1}^k \bigl( z_n-\alpha_\ell(z')\bigr)
Expand All @@ -15697,18 +15703,21 @@ \section{Hypervarieties} \label{section:hypervarieties}
The coefficients $g_\ell$ are well-defined for $z \in U' \setminus E$
as they are independent of how $\alpha_1,\ldots,\alpha_k$ are ordered.
The $g_\ell$ are holomorphic for $z \in U' \setminus E$
as locally we can choose the order so that each $\alpha_\ell$ is
holomorphic.
as locally we can ensure that each $\alpha_\ell$ is holomorphic.
The coefficients $g_\ell$ are bounded
on $U'$ and therefore extend to holomorphic functions of $U'$.
Hence, the polynomial $F$ is a polynomial
on $U'$ and so extend to holomorphic functions of $U'$
via the Riemann extension theorem.
Hence, $F$ is a polynomial
in $\sO(U')[z_n]$.
The zeros of $F$
above $z' \in U' \setminus E$
are simple and give precisely $X'$.
The zeros of $F$ above $z' \in E$, must be
limits zeros above points of $U' \setminus E$
by the argument principle.
Consequently,
the zero set of $F$ is the closure of $X'$ in $U' \times D$ by continuity.
It is left to the reader to check that %(using the argument principle)
the zero set of $F$ is the closure of $X'$ in $U' \times D$.
It is left to the reader to check that
all the functions $g_\ell$ vanish at the origin and $F$ is a Weierstrass
polynomial, a fact that will be useful in the exercises below.

Expand Down Expand Up @@ -15887,26 +15896,29 @@ \section{Hypervarieties} \label{section:hypervarieties}
$(X,p)$ meaning that its zero set is equal to $X$ near $p$.
Without loss of generality, assume that $p=0$,
and after a linear change of coordinates, assume that we can apply
the preparation theorem and \thmref{thm:discrthm} near the origin with respect to each variable
(e.g.\ if we can apply the preparation in each variable).
the preparation theorem and \thmref{thm:discrthm}
near the origin with
respect to each variable.
Then we can assume that $f$ is holomorphic in some neighborhood $W$,
$Z_f = X \cap W$, and
there exists an open neighborhood $V$ of the origin so that for every
variable $z_k$, $k=1,\ldots,n$, there is a polydisc $D=D_1 \times \cdots
\times D_n$ centered at the origin with
$\widebar{V} \subset D$ and $\widebar{D} \subset W$, where
\thmref{thm:discrthm} applies with respect to $z_k$, that is,
$Z_f \cap D_1 \times \cdots \times \partial D_k \times \cdots \times D_n =
\emptyset$.
$Z_f \cap
(D_1 \times \cdots \times \partial D_k \times \cdots \times D_n)
= \emptyset$.

Consider a $q \in X_{\textit{reg}} \cap V$. By definition, $X$ is a graph
near $q$, so we can, after reordering variables, assume it is a graph of $z_n$
near $q$, so after reordering variables,
we assume it is a graph of $z_n$
over $z'=(z_1,\ldots,z_{n-1})$.
Let $D$ be the corresponding polydisc and
write $D = D' \times D_n \subset \C^{n-1} \times \C$. Let $E \subset D'$
be the discriminant set given by the function $\Delta \in \sO(D')$.
We can think of $\Delta$ as a function in $\sO(D)$.
If $q \not\in E \times D_n$, then we have $\Delta(q) \not= 0$, so we have
We think of $\Delta$ as a function in $\sO(D)$.
If $q \not\in E \times D_n$, then $\Delta(q) \not= 0$, so we have
found a function holomorphic in $V$ that is nonzero at $q$.
Let us start a collection $\sF$ of holomorphic functions on $V$,
one for each $q \in X_{\mathit{reg}} \cap V$,
Expand Down Expand Up @@ -15948,20 +15960,23 @@ \section{Hypervarieties} \label{section:hypervarieties}
$\epsilon'$ will give us $k$ distinct intersections nearby.
See \exerciseref{exercise:nonverticalintersections}.

We take a slightly smaller polydisc
$\widetilde{D} \subset \widetilde{D}' \times D_n \subset D$
Take a slightly smaller polydisc
$\widetilde{D} = \widetilde{D}' \times D_n \subset D$
in the $\tilde{z}$ variables
such that
still $V \subset \widetilde{D}$ (we may need to pick $\epsilon'$ small
enough to arrange this), we can apply \thmref{thm:discrthm}. As the number
enough to arrange this)
and \thmref{thm:discrthm} applies in $\widetilde{D}$.
As the number
of distinct zeros of $f\bigl(\tilde{z}' + (q_n-z_n) \epsilon', z_n\bigr)$ is $m$
for all $\tilde{z}'$ near $q'$ including $\tilde{z}'=q'$,
we find that the discriminant
the discriminant
$\widetilde{\Delta}$ in these variables does not vanish at $q'$.
We againt consider $\widetilde{\Delta}$ as a function
on $V$ and as it does not vanish at $q$, we add $\widetilde{\Delta}$ to $\sF$.
See \figureref{fig:Xsingvariety} for the setup. We have finished defining
the $\sF$.
See \figureref{fig:Xsingvariety} for the setup.
We define $\sF$ by repeating for each
$q \in X_{\mathit{reg}} \cap V$.

\begin{myfig}
\medskip
Expand All @@ -15979,7 +15994,8 @@ \section{Hypervarieties} \label{section:hypervarieties}
Thus the common zero set of all the functions in $\sF$ intersected with
$X \cap V$ gives us precisely $X_{\textit{sing}} \cap V$, so
$X_{\textit{sing}}$ is a subvariety. It cannot be of dimension $n-1$ as
if it were it would be a complex submanifold of dimension $n-1$ near some
if it were,
it would be a complex submanifold of dimension $n-1$ near some
point and then not all of those points would be singular for $X$,
see \exerciseref{exercise:hypersurfaceinhypervariety}.
\end{proof}
Expand All @@ -15993,7 +16009,8 @@ \section{Hypervarieties} \label{section:hypervarieties}
$n$ discriminant functions, one for each variable.
More than $n$ functions
may be necessary as situations like the one depicted in
\figureref{fig:Xsingvariety} may occur for some $q$ no matter how we change
\figureref{fig:Xsingvariety} may occur for some $q$,
no matter how we change
variables to start with.

\begin{exbox}
Expand Down Expand Up @@ -16547,7 +16564,7 @@ \section{Segre varieties and CR geometry} \label{sec:crgeomcr}

\begin{proof}
Let $U$ be a neighborhood of $p$ where a representative
of $\Sigma_p$ is defined, that is, we assume that $\Sigma_p$ is
of $\Sigma_p$ is defined, that is, assume that $\Sigma_p$ is
a closed subset of $U$, and suppose $r(z,\bar{z})$ is the corresponding
defining function.
Let $\varphi \colon \D \to \C^n$ be the parametrization of $\Delta$
Expand All @@ -16556,7 +16573,7 @@ \section{Segre varieties and CR geometry} \label{sec:crgeomcr}
is sufficient (if there are multiple points of $\D$
that go to $p$, we repeat the argument for each one).
So let us assume without loss of generality that $\varphi(\D) = \Delta \subset U$.
Since $\Delta \subset M$ we have
Since $\Delta \subset M$, we have
\begin{equation*}
r\bigl(\varphi(\xi),\overline{\varphi(\xi)}\bigr) =
r\bigl(\varphi(\xi),\bar{\varphi}(\bar{\xi})\bigr) = 0 .
Expand Down

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