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fix
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Myyura committed Dec 25, 2024
1 parent be99290 commit ba93140
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Expand Up @@ -82,9 +82,7 @@ $$
\end{align}
$$

② について、$\int_0^{\infty}\frac{\ln x}{x^2 + 1}dx$ を求める。

$q(z) = \frac{\ln z}{z^2 + 1}$ とおくと。
② について、$\int_0^{\infty}\frac{\ln x}{x^2 + 1}dx$ を求める。$q(z) = \frac{\ln z}{z^2 + 1}$ とおくと。

$$
\begin{aligned}
Expand Down Expand Up @@ -114,13 +112,14 @@ $$
\begin{aligned}
\lim_{R \rightarrow \infty,\varepsilon \rightarrow 0}\int_{C_1}q(z)dz &= \int_0^{\infty}\frac{ln x}{x^2 + 1}dx
\end{aligned}
$$
より、
$$

より、

$$
\frac{\pi^2}{2}i = 2\int_0^{\infty}\frac{ln x}{x^2 + 1}dx
$$

より、

$$
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