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[jj7779607] Week6 #903

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Jan 18, 2025
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29 changes: 29 additions & 0 deletions container-with-most-water/limlimjo.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
/**
* @param {number[]} height
* @return {number}
*/
var maxArea = function (height) {
// Two Pointer를 이용해서 문제를 접근해야할 것 같은데 두 포인터 중에 어떤 거를 이동시켜야하는지 이 부분이 고민이 됨.
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투포인터로 접근하는 것까지 생각해내셨군요! 👍 어떤 포인터를 이동시킬 지를 고민할때는 몇가지 예시를 직접 만들어보시고 직접 눈으로 확인하는게 도움이 되는 경우가 많습니다 :)

// 그래서 이 부분은 풀이 참고
let maxArea = 0;
let start = 0,
end = height.length - 1;

while (start < end) {
// 가로 * 세로
let area = (end - start) * Math.min(height[start], height[end]);

maxArea = Math.max(area, maxArea);

// 고민했던 지점
if (height[start] < height[end]) {
start++;
} else {
end--;
}
}
return maxArea;
};

// 시간복잡도: O(n)
// 공간복잡도: O(1)
26 changes: 26 additions & 0 deletions valid-parentheses/limlimjo.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
/**
* @param {string} s
* @return {boolean}
*/
var isValid = function (s) {
// 괄호 관리 스택
const stack = [];

// 여는 괄호, 닫는 괄호 매핑
const brackets = { "(": ")", "{": "}", "[": "]" };

// for문 돌며 확인
for (let i of s) {
// 여는 괄호일 경우
if (brackets[i]) {
stack.push(brackets[i]);
// 닫는 괄호일 경우
} else if (stack.length === 0 || i !== stack.pop()) {
return false;
}
}
return stack.length === 0;
};

// 시간복잡도: O(n)
// 공간복잡도: O(n)
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