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[jj7779607] Week6 #903
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[jj7779607] Week6 #903
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,29 @@ | ||
/** | ||
* @param {number[]} height | ||
* @return {number} | ||
*/ | ||
var maxArea = function (height) { | ||
// Two Pointer를 이용해서 문제를 접근해야할 것 같은데 두 포인터 중에 어떤 거를 이동시켜야하는지 이 부분이 고민이 됨. | ||
// 그래서 이 부분은 풀이 참고 | ||
let maxArea = 0; | ||
let start = 0, | ||
end = height.length - 1; | ||
|
||
while (start < end) { | ||
// 가로 * 세로 | ||
let area = (end - start) * Math.min(height[start], height[end]); | ||
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maxArea = Math.max(area, maxArea); | ||
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// 고민했던 지점 | ||
if (height[start] < height[end]) { | ||
start++; | ||
} else { | ||
end--; | ||
} | ||
} | ||
return maxArea; | ||
}; | ||
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// 시간복잡도: O(n) | ||
// 공간복잡도: O(1) |
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---|---|---|
@@ -0,0 +1,26 @@ | ||
/** | ||
* @param {string} s | ||
* @return {boolean} | ||
*/ | ||
var isValid = function (s) { | ||
// 괄호 관리 스택 | ||
const stack = []; | ||
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// 여는 괄호, 닫는 괄호 매핑 | ||
const brackets = { "(": ")", "{": "}", "[": "]" }; | ||
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// for문 돌며 확인 | ||
for (let i of s) { | ||
// 여는 괄호일 경우 | ||
if (brackets[i]) { | ||
stack.push(brackets[i]); | ||
// 닫는 괄호일 경우 | ||
} else if (stack.length === 0 || i !== stack.pop()) { | ||
return false; | ||
} | ||
} | ||
return stack.length === 0; | ||
}; | ||
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// 시간복잡도: O(n) | ||
// 공간복잡도: O(n) |
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투포인터로 접근하는 것까지 생각해내셨군요! 👍 어떤 포인터를 이동시킬 지를 고민할때는 몇가지 예시를 직접 만들어보시고 직접 눈으로 확인하는게 도움이 되는 경우가 많습니다 :)