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import java.util.LinkedList; | ||
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// Definition for singly-linked list. | ||
class ListNode { | ||
int val; | ||
ListNode next; | ||
ListNode() {} | ||
ListNode(int val) { this.val = val; } | ||
ListNode(int val, ListNode next) { this.val = val; this.next = next; } | ||
} | ||
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class Solution { | ||
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public static void main(String[] args) { | ||
Solution s = new Solution(); | ||
var node = new ListNode(1, new ListNode(2)); | ||
s.removeNthFromEnd(node, 1); | ||
} | ||
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public ListNode removeNthFromEnd(ListNode head, int n) { | ||
// 문제: 링크드리스트의 head가 주어지면 끝에서 N번째 노드를 삭제한 결과를 반환하라 | ||
// 풀이: n번째만큼 first 이동, 그 후 second를 1칸씩 함께 이동 시킨다 first가 끝에 도달할 때 까지 | ||
// 전체 길이 L, 주어진 N이 있을때 이렇게 하면 L - N - 1 위치를 구할 수 있다. | ||
// TC: O(N) | ||
// SC: O(1) | ||
var dummy = new ListNode(-1, head); | ||
var first = head; | ||
for (int i=0; i<n; i++) { | ||
first = first.next; | ||
} | ||
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var second = dummy; | ||
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while(first != null) { | ||
first = first.next; | ||
second = second.next; | ||
} | ||
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second.next = second.next.next; | ||
return dummy.next; | ||
} | ||
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} |