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kinisoftware committed Mar 11, 2011
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70 changes: 70 additions & 0 deletions AlfredoCasado/roman_to_arabic.rb
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require "rspec"

class String

ROMAN_ARABIC_TRANSLATION = [["M", 1000],
["CM",900],
["D", 500],
["CD",400],
["C", 100],
["XC",90],
["L", 50],
["XL",40],
["X", 10],
["IX",9],
["V", 5],
["IV",4],
["I", 1]]

def to_arabic
roman_number_to_convert = self
ROMAN_ARABIC_TRANSLATION.each do |roman,arabic|
if roman_number_to_convert.start_with? roman
return arabic if roman == roman_number_to_convert
return arabic + roman_number_without_the_first(roman).to_arabic
end
end
end

def roman_number_without_the_first(roman)

self[roman.size,self.size-1]

end

end


describe "roman to arabic number converter" do

it "transform one roman character to arabic" do
"I".to_arabic.should == 1
"V".to_arabic.should == 5
"X".to_arabic.should == 10
"L".to_arabic.should == 50
"C".to_arabic.should == 100
"D".to_arabic.should == 500
"M".to_arabic.should == 1000
end

it "transform special cases with two roman characters, where the first is substracting the second, to arabic" do
"IV".to_arabic.should == 4
"IX".to_arabic.should == 9
"XL".to_arabic.should == 40
"XC".to_arabic.should == 90
"CD".to_arabic.should == 400
"CM".to_arabic.should == 900
end

it "transform two and three equal roman characters to arabic" do
"II".to_arabic.should == 2
"III".to_arabic.should == 3
end

it "transform complex roman numbers to arabic" do
"XIV".to_arabic.should == 14
"XLIX".to_arabic.should == 49
"MCMXCIX".to_arabic.should == 1999
end

end
44 changes: 44 additions & 0 deletions MuDestructor/Numerals.py
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'''
Created on 01/03/2011
@author: Fergus
'''
class Numerals:

def __init__(self):
self.romanos = {"I" : 1, "V":5, "X":10,
"L":50, "C":100, "D":500, "M":1000}
self.numeros = {1 : "I", 5:"V", 10:"X",
50:"L", 100:"C", 500:"D", 1000:"M"}
self.tuplaNumeros=(1000,500,100,50,10,5,1)
def romanoANumero(self, parametro):
'Invertir orden'
parametro=parametro[::-1]
'Recorrer numero romano'
mayor="I"
resultado=0
for letraSeleccionada in parametro:
if self.romanos[mayor] <= self.romanos[letraSeleccionada]:
resultado = resultado + self.romanos[letraSeleccionada]
mayor = letraSeleccionada
else:
resultado = resultado - self.romanos[letraSeleccionada]
return resultado
def numeroARomano(self, parametro):
resultado=""
for numero in self.tuplaNumeros:
cociente=parametro//numero;
parametro=parametro-(parametro//numero)*numero
while cociente>0:
resultado = resultado + self.numeros[numero]
cociente = cociente - 1
resultado=resultado.replace("IIII", "IV")
resultado=resultado.replace("VIV", "IX")
resultado=resultado.replace("XXXX", "XL")
resultado=resultado.replace("XXXX", "XL")
resultado=resultado.replace("LXL", "XC")
resultado=resultado.replace("CCCC", "CD")
resultado=resultado.replace("DCD", "CM")
return resultado


63 changes: 63 additions & 0 deletions MuDestructor/Tests.py
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'''
Created on 01/03/2011
@author: Fergus
'''

import unittest
from Numerals import Numerals

class Tests(unittest.TestCase):

def setUp(self):
self.numerals = Numerals()

def testGlobal(self):
self.dobleConversion("I",1)
self.dobleConversion("II", 2)
self.dobleConversion("III",3)
self.dobleConversion("IV",4)
self.dobleConversion("V",5)
self.dobleConversion("VI",6)
self.dobleConversion("VII",7)
self.dobleConversion("VIII",8)
self.dobleConversion("IX",9)
self.dobleConversion("X",10)
self.dobleConversion("XI",11)
self.dobleConversion("XII",12)
self.dobleConversion("XV",15)
self.dobleConversion("XX",20)
self.dobleConversion("XXX",30)
self.dobleConversion("XXXIX",39)
self.dobleConversion("XL",40)
self.dobleConversion("XLI",41)
self.dobleConversion("XLV",45)
self.dobleConversion("L",50)
self.dobleConversion("LX",60)
self.dobleConversion("LXX",70)
self.dobleConversion("LXXX",80)
self.dobleConversion("XC",90)
self.dobleConversion("LXIX",69)
self.dobleConversion("XCIX",99)
self.dobleConversion("CDL",450)
self.dobleConversion("DCLXVI",666)
self.dobleConversion("CMXCIX",999)
self.dobleConversion("MCDXLIV",1444)
self.dobleConversion("MCM",1900)
self.dobleConversion("MMVIII",2008)
self.dobleConversion("MMIX",2009)
self.dobleConversion("MMXI",2011)
self.dobleConversion("MMXII",2012)
self.dobleConversion("MMXIII",2013)
self.dobleConversion("MMXIV",2014)
self.dobleConversion("MMXV",2015)
self.dobleConversion("MMXVI",2016)

def dobleConversion(self, romano, numero):
mensaje = "Error al pasar " + str(romano) + " a " + str(numero) + "; resultado = " + str(self.numerals.romanoANumero(romano))
self.assertEquals(self.numerals.romanoANumero(romano),numero,mensaje)
mensaje = "Error al pasar " + str(numero) + " a " + str(romano) + "; resultado = " + str(self.numerals.numeroARomano(numero))
self.assertEquals(self.numerals.numeroARomano(numero),romano,mensaje)

if __name__ == "__main__":
unittest.main()
38 changes: 38 additions & 0 deletions README
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Problem Description

The Romans were a clever bunch. They conquered most of Europe and ruled it for hundreds of years. They invented concrete and straight roads and even bikinis[1]. One thing they never discovered though was the number zero. This made writing and dating extensive histories of their exploits slightly more challenging, but the system of numbers they came up with is still in use today. For example the BBC uses Roman numerals to date their programmes.

The Romans wrote numbers using letters - I, V, X, L, C, D, M. (notice these letters have lots of straight lines and are hence easy to hack into stone tablets)

The Kata says you should write a function to convert from normal numbers to Roman Numerals: eg

1 --> I
10 --> X
7 --> VII
etc.
For a full description of how it works, take a look at [http://www.novaroma.org/via_romana/numbers.html]: which includes an implementation of the Kata in javascript.

There is no need to be able to convert numbers larger than about 3000. (The Romans themselves didn't tend to go any higher)

Note that you can't write numerals like "IM" for 999. Wikipedia says: Modern Roman numerals ... are written by expressing each digit separately starting with the left most digit and skipping any digit with a value of zero. To see this in practice, consider the ... example of 1990. In Roman numerals 1990 is rendered: 1000=M, 900=CM, 90=XC; resulting in MCMXC. 2008 is written as 2000=MM, 8=VIII; or MMVIII.

Part II of the Kata

Write a function to convert in the other direction, ie numeral to digit
Clues

can you make the code really beautiful and highly readable?
* does it help to break out lots of small named functions from the main function, or is it better to keep it all in one function?
if you don't know an algorithm to do this already, can you derive one using strict TDD?
* does the order you take the tests in affect the final design of your algorithm?
* Would it be better to work out an algorithm first before starting with TDD?
if you do know an algorithm already, can you implement it using strict TDD?
* Can you think of another algorithm?
what are the best data structures for storing all the numeral letters? (I, V, D, M etc)
can you define the test cases in a csv file and use FIT, or generate test cases in xUnit?
what is the best way to verify your tests are correct?
Suggested Test Cases

Exercise left to the reader. You could use 1999 as an acceptance test.

URL: http://codingdojo.org/cgi-bin/wiki.pl?KataRomanNumerals
33 changes: 33 additions & 0 deletions amaneiro/roman_numerals.py
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#!/usr/bin/python

class NumericToRomanParser:

def __init__(self):
self.rosettaStone = {
1:'I',
5:'V',
10:'X',
50:'L',
100:'C',
500:'D',
1000:'M'
}

def getRomanNumber(self, number):
if (number in self.rosettaStone):
return self.rosettaStone[number]
elif number > 1000:
return 'M'+self.getRomanNumber(number-1000)
elif number > 500:
return 'D'+self.getRomanNumber(number-500)
elif number > 100:
return 'C'+self.getRomanNumber(number-100)
elif number > 50:
return 'L'+self.getRomanNumber(number-50)
elif number > 10:
return 'X'*(number/10)+self.getRomanNumber(number%10)
elif number > 5:
return 'V'+'I'*(number-5)
else:
return 'I'*number

57 changes: 57 additions & 0 deletions amaneiro/test_numeric2roman_parser.py
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#!/usr/bin/python

import unittest
from roman_numerals import NumericToRomanParser

class NumericToRomanParserTestCase(unittest.TestCase):

def setUp(self):
self.parser = NumericToRomanParser()

def testMainSymbols(self):
self.assertEqual(self.parser.getRomanNumber(1), 'I')
self.assertEqual(self.parser.getRomanNumber(5), 'V')
self.assertEqual(self.parser.getRomanNumber(10), 'X')
self.assertEqual(self.parser.getRomanNumber(50), 'L')
self.assertEqual(self.parser.getRomanNumber(100), 'C')
self.assertEqual(self.parser.getRomanNumber(500), 'D')
self.assertEqual(self.parser.getRomanNumber(1000), 'M')

def testNumbersLowerThanFive(self):
self.assertEqual(self.parser.getRomanNumber(2), 'II')
self.assertEqual(self.parser.getRomanNumber(3), 'III')
self.assertEqual(self.parser.getRomanNumber(4), 'IIII')

def testNumbersBetweenFiveAndTen(self):
self.assertEqual(self.parser.getRomanNumber(6), 'VI')
self.assertEqual(self.parser.getRomanNumber(7), 'VII')
self.assertEqual(self.parser.getRomanNumber(8), 'VIII')
self.assertEqual(self.parser.getRomanNumber(9), 'VIIII')

def testNumbersBetweenXAndL(self):
self.assertEqual(self.parser.getRomanNumber(11), 'XI')
self.assertEqual(self.parser.getRomanNumber(15), 'XV')
self.assertEqual(self.parser.getRomanNumber(23), 'XXIII')
self.assertEqual(self.parser.getRomanNumber(29), 'XXVIIII')

def testMeaningOfLife(self):
self.assertEqual(self.parser.getRomanNumber(42), 'XXXXII')

def testNumbersBetweenLAndC(self):
self.assertEqual(self.parser.getRomanNumber(51), 'LI')
self.assertEqual(self.parser.getRomanNumber(99), 'LXXXXVIIII')

def testNumbersBetweenCAndD(self):
self.assertEqual(self.parser.getRomanNumber(105), 'CV')
self.assertEqual(self.parser.getRomanNumber(205), 'CCV')
self.assertEqual(self.parser.getRomanNumber(399), 'CCCLXXXXVIIII')

def testNumbersBetweenDAndM(self):
self.assertEqual(self.parser.getRomanNumber(501), 'DI')

def testNumbersBetweenMAndMMM(self):
self.assertEqual(self.parser.getRomanNumber(1999), 'MDCCCCLXXXXVIIII')
self.assertEqual(self.parser.getRomanNumber(2956), 'MMDCCCCLVI')

if __name__ == '__main__':
unittest.main()
7 changes: 7 additions & 0 deletions amedio/README
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La kata ha sido realizada con recursividad

La funcion recursiva mantiene el numero a tratar y el tama�o de la string del n�mero a efectos de decidir si los 1s y los 5s se traducen a Is, Xs, Cs o Ms y a Vs, Ls o Ds, respectivamente

Estoy abierto a comentarios.

Gracias
3 changes: 3 additions & 0 deletions amuino/.gitignore
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.idea
target
*.iml
9 changes: 9 additions & 0 deletions amuino/cucumber/README.txt
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Implementación de la Kata de números romanos
============================================

Lenguaje: Ruby
Pruebas: Cucumber + RSpec
Estilo: Sin hashes con números romanos "extra" (IX, IV, etc…).

--
amuino
41 changes: 41 additions & 0 deletions amuino/cucumber/converter.rb
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class Fixnum
ROMAN_ONES = ["I", "X", "C", "M"]
ROMAN_FIVES = ["V", "L", "D", ""]

def to_roman
return nil if self < 1 || self >= 4000
current = self
[3,2,1,0].inject("") do |result, power|
div, mod = current.divmod(10**power)
current = mod
result + digit_to_roman(div, power)
end
end

def digit_to_roman(digit, scale)
five_or_more, less_than_five = digit.divmod(5)
case less_than_five
when 4 then ROMAN_ONES[scale] + (five_or_more == 1 ? ROMAN_ONES[scale+1] : ROMAN_FIVES[scale])
else ROMAN_FIVES[scale]*five_or_more + ROMAN_ONES[scale]*less_than_five
end
end
end

class String
ROMAN_VALUES = {"M" => 1000, "D" => 500, "C" => 100, "L" => 50, "X" => 10, "V" => 5, "I" => 1}

def from_roman
integer = (self.chars.to_a << nil).each_cons(2).inject(0) do |result, digits|
current_digit, next_digit = from_roman_letter(digits.first), from_roman_letter(digits.last).to_i
return nil if current_digit.nil? || next_digit.nil?
sign = (current_digit < next_digit) ? -1 : +1
result += sign * current_digit
end
return integer if integer.to_roman == self
nil
end

def from_roman_letter(value)
return ROMAN_VALUES[value]
end
end
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