From c96738ecd59e6b6f298be8e621da120401337f67 Mon Sep 17 00:00:00 2001
From: yixy <34703796+yixy-only@users.noreply.github.com>
Date: Tue, 9 Jul 2024 02:07:31 +0800
Subject: [PATCH] =?UTF-8?q?Fix:=20=E4=BF=AE=E5=A4=8D=20keystate=20?=
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使用 GetOpenFileName 等打开对话框后，keystate 失效，但按键消息正常。原因是 GetKeyState 是通过处理按键消息来判断按键状态，需要在消息队列的窗口线程中使用。（如果在其它线程，猜测目前的底层实现是会获取最新创建的一个窗口线程的按键状态，因此一开始未打开对话框时是正常的。）。
chore: 忽略 ./out 目录 (Visual Studio Cmake生成目录)
---
 .gitignore       | 1 +
 src/keyboard.cpp | 5 +----
 2 files changed, 2 insertions(+), 4 deletions(-)

diff --git a/.gitignore b/.gitignore
index 0771e018..ed85a741 100644
--- a/.gitignore
+++ b/.gitignore
@@ -11,3 +11,4 @@
 
 /build
 /temp
+/out
diff --git a/src/keyboard.cpp b/src/keyboard.cpp
index d9a97361..2a4ccc83 100644
--- a/src/keyboard.cpp
+++ b/src/keyboard.cpp
@@ -229,10 +229,7 @@ int keystate(int key)
     if (key < 0 || key >= MAX_KEY_VCODE) {
         return -1;
     }
-    SHORT s = GetKeyState(key);
-    if (((USHORT)s & 0x8000) == 0) {
-        pg->keystatemap[key] = 0;
-    }
+
     return pg->keystatemap[key];
 }