| layout | title | permalink |
|---|---|---|
page |
Q49573: sscanf with %i and a Leading 0 Gives Octal Conversion Results |
/pubs/pc/reference/microsoft/kb/Q49573/ |
Article: Q49573
Version(s): 5.10 | 5.10
Operating System: MS-DOS | OS/2
Flags: ENDUSER | S_QuickC S_QuickASM scanf sscanf fscanf
Last Modified: 22-NOV-1989
Question:
Why does sscanf return incorrect results when I use the %i switch, yet
it returns correct results when I use the %d switch?
Response:
The %i switch has the capability of reading in decimal, octal, and
hexadecimal numbers. Hexadecimal numbers are specified with the 0x in
front of the number, while octal numbers are specified with the 0
(zero) in front of them. If you want only decimal numbers to be read
in, use the %d switch.
This is expected behavior and occurs with the entire scanf family.