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Feynman integral having two linear propagators #4
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I'm not a pySecDec developer (just a fellow user of the package), but if I'm not mistaken the automatic derivation On the contrary, here you have a true Cartesian D-1 dimensional integral, which is something completely different, so no You could also employ FeynCalc's FCFeynmanParametrize if you need to derive parametrization for a larger number of
Hope this helps. |
I think the problem persists if you consider the Minkowskian metric. |
Indeed, if one only looks at the ratio, the prefactors (Minkowski vs. Euclidean) should drop out |
We apologize for our slow reply. We thank Vladyslav, Go, and Stephen for helpful comments. The new note is here: Feynman.pdf. The main point is summarized in the first 3 pages. We also attach the code here: Feynman.zip.
Thank you for your help! |
Many thanks for the detailed answer and this enlightening discussion. It's interesting that the poles of the F-polynomial at If I consider the full F-polynomial -1/4*(x[2]^2x[3]) - (x[1]^2x[4])/4 - (x[1]^2*x[5])/4 + (x[1]*x[2]x[5])/2 - (x[2]^2x[5])/4 + x[3]*x[4]*x[5] and calculate the Groebner basis of F and
So there is a non-trivial way to satisfy the Landau equations by putting 4 of the 5 Feynman parameters to zero, How does pySecDec actually handle the search for zeros of the F-polynomials? |
In the full F-polynomial you consider, when x[1]=x[2] and x[3]=x[4]=0, then you have F=0 and dF/dx[1]=dF/dx[2]=dF/dx[5]=0. It is true that the F polynomial after sector decomposition is different, it has different variables and terms are factorized out, such that F has a constant term. For the new F in the new variables the contour deformation is used to try to go around the remaining poles of F. In general there is no search for zeros of the F-polynomial, some zeros are factorized out using sector decomposition and for the remaining ones contour deformation is used, but contour deformation doesn't always go around all of them (when they are at endpoints or when dF/dx=0). Only with the split option, after sector decomposition, it tries to find all variables which when set to one in any combination result in no constant term in the polynomials it is integrating. It then splits the integration domain 0 to 1 into two parts 0 to a and a to 1, then maps x->1-x in the second one and does sector decomposition again. |
The issue is about an integral having two linear propagators
Here the momenta are Euclidean,
and
are orthogonal vectors
, the dimension is
, and the
prescription is implicit. The analytic result should be
but seemingly pysecdec does not reproduce the ratio 2:1 between the two. The derivation is summarized here Feynman.pdf, and an example code is here Feynman.zip.
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