From 04a0eb54fac1762e1fb9b432c9be09b32ae9f4f9 Mon Sep 17 00:00:00 2001
From: yubin <59639035+gogumaC@users.noreply.github.com>
Date: Sat, 4 Jan 2025 16:41:46 +0900
Subject: [PATCH] Delete 0009-palindrome-number directory
---
.../0009-palindrome-number.c | 29 ---------------
0009-palindrome-number/README.md | 36 -------------------
2 files changed, 65 deletions(-)
delete mode 100644 0009-palindrome-number/0009-palindrome-number.c
delete mode 100644 0009-palindrome-number/README.md
diff --git a/0009-palindrome-number/0009-palindrome-number.c b/0009-palindrome-number/0009-palindrome-number.c
deleted file mode 100644
index 6b85f4b..0000000
--- a/0009-palindrome-number/0009-palindrome-number.c
+++ /dev/null
@@ -1,29 +0,0 @@
-bool isPalindrome(int x) {
-
- int len = 0;
- int xx = x;
- do
- {
- xx/=10;
- len++;
- }while(xx);
-
- if(x<0)
- {
- len++;
- }
-
- char str[len+1];
- sprintf(str,"%d",x);
-
- for(int i=0; i<=len/2; i++)
- {
- if(str[i]!=str[len-i-1])
- {
- return false;
- }
- }
-
- return true;
-
-}
\ No newline at end of file
diff --git a/0009-palindrome-number/README.md b/0009-palindrome-number/README.md
deleted file mode 100644
index 6fa224a..0000000
--- a/0009-palindrome-number/README.md
+++ /dev/null
@@ -1,36 +0,0 @@
-Easy
Given an integer x, return true if x is a palindrome, and false otherwise.
-
-
-Example 1:
-
-
-Input: x = 121
-Output: true
-Explanation: 121 reads as 121 from left to right and from right to left.
-
-
-Example 2:
-
-
-Input: x = -121
-Output: false
-Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
-
-
-Example 3:
-
-
-Input: x = 10
-Output: false
-Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
-
-
-
-Constraints:
-
-
-
-
-Follow up: Could you solve it without converting the integer to a string?
\ No newline at end of file