leetcode/en/lcci/1.1/

[giscus[bot]]

leetcode/en/lcci/1.1/

LeetCode solutions in any programming language

https://doocs.github.io/leetcode/en/lcci/1.1/

[jumael99]

Hi! Without bit manipulation can you give some other easy solution?

[devmustafa03]

const isCheckingSimilarCharacter = (word) => {
const currentWord = new Set();

for (let char of word) {
    if (currentWord.has(char)) {
        return false;
    }
    currentWord.add(char);
}

return true;

};

This is for javascript

[rajputanisha]

#include <bits/stdc++.h>
using namespace std;
bool fun(string s,int n ){
unordered_map<char,int>mp;
for(auto it :s){
mp[it]++;
}
for(auto it :mp){
if(it.second>1){
return false;
}

}
return true;
}
int main()
{
string s = "lswtcde";
int n = s.size();
bool ans = fun(s, n);
cout << ans << endl;

return 0;

}

[rajputanisha]

In this we use map to store the key value pair. If count greater than one means there are duplicate present . we simply return false. otherwise we will simply return true if count of all elements are equal to one. i e all elements are unique
map store element like this for example string example = "Leetcode"
L ->1
e ->2
t ->1
c ->1
o ->1
d ->1
e ->1
this is simple representation of unordered_map