How to infer required keys in object with z.infer?

[arn4v]

Edit: It was an issue with a mismerge that removed strict: true

---

I have the following schema and type alias:

export const createEventPayloadSchema = z
  .object({
    name: z.string(),
    userId: z.string(),
    environment: z.object({
      type: z.union([z.literal("server"), z.literal("browser")]),
      platform: z.string(),
      pageUrl: z.string(),
    }),
    time: z.string(),
    properties: z.record(z.union([z.string(), z.number(), z.null()])),
  })
  .required();

export type CreateEventPayload = z.infer<typeof createEventPayloadSchema>;

In this schema, I need the types not explicitly marked as .optional() to be required in the inferred type. However, this is what z.infer gives me:

type CreateEventPayload = {
    name?: string;
    userId?: string;
    environment?: {
        type?: "server" | "browser";
        platform?: string;
        pageUrl?: string;
    };
    time?: string;
    properties?: Record<string, string | number>;
}

Here, the name and environment key should not be optional.

How do I circumvent this?

[arn4v]

Fixed: It was an issue with a mismerge that removed strict: true