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Let $x_1, \dots, x_n$ be vectors of norm at least $1$ a normed space. For $A \subseteq [n]$, set $x_A =
\sum_{i \in A} x_i$. Let $\McA \subseteq 2^{[n]}$ be such that $$\forall A, B \in \McA, ||x_A - x_B|| < 1$$
Then $|\McA| \le {n \choose \lfloor\frac n2\rfloor}$.
Let$x_1, \dots, x_n$ be vectors of norm at least $1$ a normed space. For $A \subseteq [n]$ , set $x_A =$\McA \subseteq 2^{[n]}$ be such that
$$\forall A, B \in \McA, ||x_A - x_B|| < 1$$ $|\McA| \le {n \choose \lfloor\frac n2\rfloor}$ .
\sum_{i \in A} x_i$. Let
Then
This is Theorem 1.12 in the lecture notes and there is a start over at #21.
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