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mergeoverlapping.java
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package aryanhere.Striver;
import java.util.*;
public class mergeoverlapping {
public static ArrayList<ArrayList<Integer>> mergeOverlapping(int arr[][]) {
int n = arr.length;
Arrays.sort(arr, new Comparator<int[]>() {
public int compare(int[] a, int[] b) {
return a[0] - b[0];
}
});
ArrayList<ArrayList<Integer>> ans = new ArrayList<>();
for (int i = 0; i < n; i++) {
int start = arr[i][0];
int end = arr[i][1];
if (!ans.isEmpty() && end <= ans.get(ans.size() - 1).get(1)) {
continue;
}
for (int j = i + 1; j < n; j++) {
if (arr[j][0] <= end) {
end = Math.max(end, arr[j][1]);
} else {
break;
}
}
ans.add(new ArrayList<>(Arrays.asList(start, end)));
}
// time complexity (O(NlogN)) + O(2*N)
// if i tell u honestly i revised it multiple times did a dry run mltiple times then i got this ..
return ans;
}
public static ArrayList<ArrayList<Integer>> mergeOverlapping1(int arr[][]) {
int n = arr.length;
Arrays.sort(arr, new Comparator<int[]>() {
public int compare(int[] a, int[] b) {
return a[0] - b[0];
}
});
ArrayList<ArrayList<Integer>> ans = new ArrayList<>();
for (int i = 0; i < n; i++) {
if (ans.isEmpty() || arr[i][0] > ans.get(ans.size() - 1).get(1)) {
ans.add(new ArrayList<>(Arrays.asList(arr[i][0], arr[i][1])));
} else {
ans.get(ans.size() - 1).set(1, Math.max(ans.get(ans.size() - 1).get(1), arr[i][1]));
}
}
return ans;
}
public static void main(String[] args) {
int arr[][] = {{1, 3}, {8, 10}, {2, 6}, {15, 18}};
ArrayList<ArrayList<Integer>> ans = mergeOverlapping1(arr);
System.out.println("The merged arrays are:\n");
for (ArrayList<Integer> aa : ans) {
System.out.print("[" + aa.get(0) + " , " + aa.get(1) + "]");
}
System.out.println();
}
}