John has some amount of money of which he wants to deposit a part f0
to the bank at the beginning
of year 1
. He wants to withdraw each year for his living an amount c0
.
Here is his banker plan:
- deposit
f0
at beginning of year 1 - his bank account has an interest rate of
p
percent per year, constant over the years - John can withdraw each year
c0
, taking it whenever he wants in the year; he must take account of an inflation ofi
percent per year in order to keep his quality of living.i
is supposed to stay constant over the years. - all amounts
f0
..fn-1
,c0
..cn-1
are truncated by the bank to their integral part - Given
f0
,p
,c0
,i
the banker guarantees that John will be able to go on that way until thenth
year.
f0 = 100000, p = 1 percent, c0 = 2000, n = 15, i = 1 percent
beginning of year 2 -> f1 = 100000 + 0.01*100000 - 2000 = 99000; c1 = c0 + c0*0.01 = 2020 (with inflation of previous year)
beginning of year 3 -> f2 = 99000 + 0.01*99000 - 2020 = 97970; c2 = c1 + c1*0.01 = 2040.20
(with inflation of previous year, truncated to 2040)
beginning of year 4 -> f3 = 97970 + 0.01*97970 - 2040 = 96909.7 (truncated to 96909);
c3 = c2 + c2*0.01 = 2060.4 (with inflation of previous year, truncated to 2060)
and so on...
John wants to know if the banker's plan is right or wrong.
Given parameters f0, p, c0, n, i
build a function fortune
which returns true
if John can make a living until the nth
year
and false
if it is not possible.
fortune(100000, 1, 2000, 15, 1) -> True
fortune(100000, 1, 10000, 10, 1) -> True
fortune(100000, 1, 9185, 12, 1) -> False
For the last case you can find below the amounts of his account at the beginning of each year:
100000, 91815, 83457, 74923, 66211, 57318, 48241, 38977, 29523, 19877, 10035, -5
f11 = -5 so he has no way to withdraw something for his living in year 12.
Note: Don't forget to convert the percent parameters as percentages in the body of your function: if a parameter percent is 2 you have to convert it to 0.02.