README_EN.md

2600. K Items With the Maximum Sum

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Description

There is a bag that consists of items, each item has a number 1, 0, or -1 written on it.

You are given four non-negative integers numOnes, numZeros, numNegOnes, and k.

The bag initially contains:

• numOnes items with 1s written on them.
• numZeroes items with 0s written on them.
• numNegOnes items with -1s written on them.

We want to pick exactly k items among the available items. Return the maximum possible sum of numbers written on the items.

 

Example 1:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2
Output: 2
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2.
It can be proven that 2 is the maximum possible sum.

Example 2:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4
Output: 3
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3.
It can be proven that 3 is the maximum possible sum.

 

Constraints:

• 0 <= numOnes, numZeros, numNegOnes <= 50
• 0 <= k <= numOnes + numZeros + numNegOnes

Solutions

Python3

class Solution:
    def kItemsWithMaximumSum(self, numOnes: int, numZeros: int, numNegOnes: int, k: int) -> int:
        if numOnes >= k:
            return k
        k -= numOnes
        if numZeros >= k:
            return numOnes
        k -= numZeros
        return numOnes - k

Java

class Solution {
    public int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
        if (numOnes >= k) {
            return k;
        }
        k -= numOnes;
        if (numZeros >= k) {
            return numOnes;
        }
        k -= numZeros;
        return numOnes - k;
    }
}

C++

class Solution {
public:
    int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
        if (numOnes >= k) {
            return k;
        }
        k -= numOnes;
        if (numZeros >= k) {
            return numOnes;
        }
        k -= numZeros;
        return numOnes - k;
    }
};

Go

func kItemsWithMaximumSum(numOnes int, numZeros int, numNegOnes int, k int) int {
	if numOnes >= k {
		return k
	}
	k -= numOnes
	if numZeros >= k {
		return numOnes
	}
	k -= numZeros
	return numOnes - k
}

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