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Description

There are n flights that are labeled from 1 to n.

You are given an array of flight bookings bookings, where bookings[i] = [firsti, lasti, seatsi] represents a booking for flights firsti through lasti (inclusive) with seatsi seats reserved for each flight in the range.

Return an array answer of length n, where answer[i] is the total number of seats reserved for flight i.

 

Example 1:

Input: bookings = [[1,2,10],[2,3,20],[2,5,25]], n = 5
Output: [10,55,45,25,25]
Explanation:
Flight labels:        1   2   3   4   5
Booking 1 reserved:  10  10
Booking 2 reserved:      20  20
Booking 3 reserved:      25  25  25  25
Total seats:         10  55  45  25  25
Hence, answer = [10,55,45,25,25]

Example 2:

Input: bookings = [[1,2,10],[2,2,15]], n = 2
Output: [10,25]
Explanation:
Flight labels:        1   2
Booking 1 reserved:  10  10
Booking 2 reserved:      15
Total seats:         10  25
Hence, answer = [10,25]

 

Constraints:

  • 1 <= n <= 2 * 104
  • 1 <= bookings.length <= 2 * 104
  • bookings[i].length == 3
  • 1 <= firsti <= lasti <= n
  • 1 <= seatsi <= 104

Solutions

Python3

class Solution:
    def corpFlightBookings(self, bookings: List[List[int]], n: int) -> List[int]:
        ans = [0] * n
        for first, last, seats in bookings:
            ans[first - 1] += seats
            if last < n:
                ans[last] -= seats
        return list(accumulate(ans))
class BinaryIndexedTree:
    def __init__(self, n):
        self.n = n
        self.c = [0] * (n + 1)

    def update(self, x, delta):
        while x <= self.n:
            self.c[x] += delta
            x += x & -x

    def query(self, x):
        s = 0
        while x:
            s += self.c[x]
            x -= x & -x
        return s


class Solution:
    def corpFlightBookings(self, bookings: List[List[int]], n: int) -> List[int]:
        tree = BinaryIndexedTree(n)
        for first, last, seats in bookings:
            tree.update(first, seats)
            tree.update(last + 1, -seats)
        return [tree.query(i + 1) for i in range(n)]

Java

class Solution {
    public int[] corpFlightBookings(int[][] bookings, int n) {
        int[] ans = new int[n];
        for (var e : bookings) {
            int first = e[0], last = e[1], seats = e[2];
            ans[first - 1] += seats;
            if (last < n) {
                ans[last] -= seats;
            }
        }
        for (int i = 1; i < n; ++i) {
            ans[i] += ans[i - 1];
        }
        return ans;
    }
}
class Solution {
    public int[] corpFlightBookings(int[][] bookings, int n) {
        BinaryIndexedTree tree = new BinaryIndexedTree(n);
        for (var e : bookings) {
            int first =e[0], last = e[1], seats = e[2];
            tree.update(first, seats);
            tree.update(last + 1, -seats);
        }
        int[] ans = new int[n];
        for (int i = 0; i < n; ++i) {
            ans[i] = tree.query(i + 1);
        }
        return ans;
    }
}

class BinaryIndexedTree {
    private int n;
    private int[] c;

    public BinaryIndexedTree(int n) {
        this.n = n;
        c = new int[n + 1];
    }

    public void update(int x, int delta) {
        while (x <= n) {
            c[x] += delta;
            x += x & -x;
        }
    }

    public int query(int x) {
        int s = 0;
        while (x > 0) {
            s += c[x];
            x -= x & -x;
        }
        return s;
    }
}

C++

class Solution {
public:
    vector<int> corpFlightBookings(vector<vector<int>>& bookings, int n) {
        vector<int> ans(n);
        for (auto& e : bookings) {
            int first = e[0], last = e[1], seats = e[2];
            ans[first - 1] += seats;
            if (last < n) {
                ans[last] -= seats;
            }
        }
        for (int i = 1; i < n; ++i) {
            ans[i] += ans[i - 1];
        }
        return ans;
    }
};
class BinaryIndexedTree {
public:
    BinaryIndexedTree(int _n): n(_n), c(_n + 1){}

    void update(int x, int delta) {
        while (x <= n) {
            c[x] += delta;
            x += x & -x;
        }
    }

    int query(int x) {
        int s = 0;
        while (x) {
            s += c[x];
            x -= x & -x;
        }
        return s;
    }

private:
    int n;
    vector<int> c;
};

class Solution {
public:
    vector<int> corpFlightBookings(vector<vector<int>>& bookings, int n) {
        BinaryIndexedTree* tree = new BinaryIndexedTree(n);
        for (auto& e : bookings) {
            int first = e[0], last = e[1], seats = e[2];
            tree->update(first, seats);
            tree->update(last + 1, -seats);
        }
        vector<int> ans(n);
        for (int i = 0; i < n; ++i) {
            ans[i] = tree->query(i + 1);
        }
        return ans;
    }
};

Go

func corpFlightBookings(bookings [][]int, n int) []int {
	ans := make([]int, n)
	for _, e := range bookings {
		first, last, seats := e[0], e[1], e[2]
		ans[first-1] += seats
		if last < n {
			ans[last] -= seats
		}
	}
	for i := 1; i < n; i++ {
		ans[i] += ans[i-1]
	}
	return ans
}
type BinaryIndexedTree struct {
	n int
	c []int
}

func newBinaryIndexedTree(n int) *BinaryIndexedTree {
	c := make([]int, n+1)
	return &BinaryIndexedTree{n, c}
}

func (this *BinaryIndexedTree) update(x, delta int) {
	for x <= this.n {
		this.c[x] += delta
		x += x & -x
	}
}

func (this *BinaryIndexedTree) query(x int) int {
	s := 0
	for x > 0 {
		s += this.c[x]
		x -= x & -x
	}
	return s
}

func corpFlightBookings(bookings [][]int, n int) []int {
	tree := newBinaryIndexedTree(n)
	for _, e := range bookings {
		first, last, seats := e[0], e[1], e[2]
		tree.update(first, seats)
		tree.update(last+1, -seats)
	}
	ans := make([]int, n)
	for i := range ans {
		ans[i] = tree.query(i + 1)
	}
	return ans
}

JavaScript

/**
 * @param {number[][]} bookings
 * @param {number} n
 * @return {number[]}
 */
var corpFlightBookings = function (bookings, n) {
    const ans = new Array(n).fill(0);
    for (const [first, last, seats] of bookings) {
        ans[first - 1] += seats;
        if (last < n) {
            ans[last] -= seats;
        }
    }
    for (let i = 1; i < n; ++i) {
        ans[i] += ans[i - 1];
    }
    return ans;
};

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