README_EN.md

1023. Camelcase Matching

中文文档

Description

Given an array of strings queries and a string pattern, return a boolean array answer where answer[i] is true if queries[i] matches pattern, and false otherwise.

A query word queries[i] matches pattern if you can insert lowercase English letters pattern so that it equals the query. You may insert each character at any position and you may not insert any characters.

 

Example 1:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
Output: [true,false,true,true,false]
Explanation: "FooBar" can be generated like this "F" + "oo" + "B" + "ar".
"FootBall" can be generated like this "F" + "oot" + "B" + "all".
"FrameBuffer" can be generated like this "F" + "rame" + "B" + "uffer".

Example 2:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
Output: [true,false,true,false,false]
Explanation: "FooBar" can be generated like this "Fo" + "o" + "Ba" + "r".
"FootBall" can be generated like this "Fo" + "ot" + "Ba" + "ll".

Example 3:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
Output: [false,true,false,false,false]
Explanation: "FooBarTest" can be generated like this "Fo" + "o" + "Ba" + "r" + "T" + "est".

 

Constraints:

• 1 <= pattern.length, queries.length <= 100
• 1 <= queries[i].length <= 100
• queries[i] and pattern consist of English letters.

Solutions

Python3

class Solution:
    def camelMatch(self, queries: List[str], pattern: str) -> List[bool]:
        def check(s, t):
            m, n = len(s), len(t)
            i = j = 0
            while j < n:
                while i < m and s[i] != t[j] and s[i].islower():
                    i += 1
                if i == m or s[i] != t[j]:
                    return False
                i, j = i + 1, j + 1
            while i < m and s[i].islower():
                i += 1
            return i == m

        return [check(q, pattern) for q in queries]

Java

class Solution {
    public List<Boolean> camelMatch(String[] queries, String pattern) {
        List<Boolean> ans = new ArrayList<>();
        for (var q : queries) {
            ans.add(check(q, pattern));
        }
        return ans;
    }

    private boolean check(String s, String t) {
        int m = s.length(), n = t.length();
        int i = 0, j = 0;
        for (; j < n; ++i, ++j) {
            while (i < m && s.charAt(i) != t.charAt(j) && Character.isLowerCase(s.charAt(i))) {
                ++i;
            }
            if (i == m || s.charAt(i) != t.charAt(j)) {
                return false;
            }
        }
        while (i < m && Character.isLowerCase(s.charAt(i))) {
            ++i;
        }
        return i == m;
    }
}

C++

class Solution {
public:
    vector<bool> camelMatch(vector<string>& queries, string pattern) {
        vector<bool> ans;
        auto check = [](string& s, string& t) {
            int m = s.size(), n = t.size();
            int i = 0, j = 0;
            for (; j < n; ++i, ++j) {
                while (i < m && s[i] != t[j] && islower(s[i])) {
                    ++i;
                }
                if (i == m || s[i] != t[j]) {
                    return false;
                }
            }
            while (i < m && islower(s[i])) {
                ++i;
            }
            return i == m;
        };
        for (auto& q : queries) {
            ans.push_back(check(q, pattern));
        }
        return ans;
    }
};

Go

func camelMatch(queries []string, pattern string) (ans []bool) {
	check := func(s, t string) bool {
		m, n := len(s), len(t)
		i, j := 0, 0
		for ; j < n; i, j = i+1, j+1 {
			for i < m && s[i] != t[j] && (s[i] >= 'a' && s[i] <= 'z') {
				i++
			}
			if i == m || s[i] != t[j] {
				return false
			}
		}
		for i < m && s[i] >= 'a' && s[i] <= 'z' {
			i++
		}
		return i == m
	}
	for _, q := range queries {
		ans = append(ans, check(q, pattern))
	}
	return
}

TypeScript

function camelMatch(queries: string[], pattern: string): boolean[] {
    const check = (s: string, t: string) => {
        const m = s.length;
        const n = t.length;
        let i = 0;
        let j = 0;
        for (; j < n; ++i, ++j) {
            while (i < m && s[i] !== t[j] && s[i].codePointAt(0) >= 97) {
                ++i;
            }
            if (i === m || s[i] !== t[j]) {
                return false;
            }
        }
        while (i < m && s[i].codePointAt(0) >= 97) {
            ++i;
        }
        return i == m;
    };
    const ans: boolean[] = [];
    for (const q of queries) {
        ans.push(check(q, pattern));
    }
    return ans;
}

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